At 1.00 atmosphere pressure, a certain mass of a gas has a temperature of 100oc. what will be the temperature at 1.13 atmosphere pressure if the volume remains constant?

 Final temperature of the gas will be 330 K.

Explanation:

Gay-Lussac's Law: This law states that pressure is directly proportional to the temperature of the gas at constant volume and number of moles.

    (At constant volume and number of moles)

where,

= initial pressure of gas   = 1.00 atm

= final pressure of gas  = 1.13 atm

= initial temperature of gas  = K

= final temperature of gas  = ?

Therefore, the final temperature of the gas will be 330 K.

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consider the reaction below.

 no rx

at 500 k, the reaction is at equilibrium with the following concentrations.

[pci5]= 0.0095 m

[pci3] = 0.020

[ci2] = 0.020 m

what is the equilibrium constant for the given reaction?

0.042

0.42

2.4

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