Prob.: consider the combustion of butane (c4h10):
2c4h10(g) + 13o2(g) ==> 8co2(g) + 10 h2o(l)
in a particular reaction, 5.0 moles of c4h10 are reacted
withan excess of o2. calculate the number of moles of co2
formed.

The moles of carbon dioxide formed in the reaction is 20 moles.

Explanation:

We are given:

Number of moles of butane = 5.0 moles

The chemical reaction for the combustion of butane follows the equation:

As, oxygen is present in excess. So, it is considered as an excess reagent.

Thus, butane is considered as a limiting reagent because it limits the formation of products.

By stoichiometry of the reaction:

2 moles of butane produces 8 moles of carbon dioxide.

So, 5 moles of butane will produce = of carbon dioxide.

Hence, the moles of carbon dioxide formed in the reaction is 20 moles.