How do you calculate the ph of a 1.6 m koh solution?

14.20

Explanation:

The pH can be calculated as:

KOH is a strong base and it will dissociate completely in the solution as:

According to the equation and also mentioned that KOH will dissociate completely. So,

Molarity of the hydroxide ions furnished = Molarity of the KOH = 1.6 M

So,

pOH = -log[OH⁻] = -log(1.6) = -0.20

Also,  

pH + pOH = 14  

So, pH = 14 - ( - 0.20 ) = 14.20

rosa was looking for patterns to predict the products of chemical reactions. she recorded three similar decomposition reactions in the table.she should record 2licl + 3o2.

in the last row of the table. it is the thermal decomposition of chlorate lithium, hence, she should record these products as: lithium chloride ( 2licl ) and oxygen ( 3o2 )   2 > 2 licl + 3o2.