Asolution is to be prepared with a sodium ion concentrationof
0.148 mol/l. what mass of sodium sulfate (g) is needed toprepare
2.29 liters of such a solution?

Answer : The mass of sodium sulfate needed is 5.7085 grams.

Explanation : Given,

Concentration of sodium ion = 0.148 mol/L

Volume of solution = 2.29 L

Molar mass of sodium sulfate = 142 g/mole

First we have to determine the moles of sodium ion.

Now we have to calculate the moles of sodium sulfate.

The balanced chemical reaction will be,

As, 2 moles of sodium ion produced from 1 moles of

So, 0.08035 moles of sodium ion produced from moles of

Now we have to calculate the mass of sodium sulfate.

Therefore, the mass of sodium sulfate needed is 5.7085 grams.

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