Chemistry, 12.09.2019 20:30 alexdziob01
Using the thermodynamic information in the aleks data tab, calculate the standard reaction entropy of the following chemical reaction:
p4o10 + 6h2o → 4h3po4
round your answer to zero decimal places.
Answers: 1
for the reaction is -206 J/K![\Delta S^o_{rxn}=\sum [n\times \Delta S^o_{(product)}]-\sum [n\times \Delta S^o_{(reactant)}]](/tpl/images/0229/0964/52737.png)
![\Delta S^o_{rxn}=[(4\times \Delta S^o_{(H_3PO_4)})]-[(1\times \Delta S^o_{(P_4O_{10})})+(6\times \Delta S^o_{(H_2O)})]](/tpl/images/0229/0964/8072b.png)
![\Delta S^o_{rxn}=[(4\times (110.5))]-[(1\times (228.86))+(6\times (69.91))]\\\\\Delta S^o_{rxn}=-206.32J/K=-206J/K](/tpl/images/0229/0964/7ca19.png)
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Using the thermodynamic information in the aleks data tab, calculate the standard reaction entropy o...
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