Methane and chlorine react to form four products: ch3cl, ch2cl2, chcl3, and ccl4. at a particular temperature and pressure, 38.4 g of ch4 was allowed to react with excess cl2 and gave 9.2 g ch3cl, 47.1 g ch2cl2, and 109 g chcl3. all the ch4 reacted. (note: the hydrogen that is displaced from the carbon also combines with cl2 to form hcl.)how many grams of ccl4 were formed? how many grams of cl2 reacted with the ch4?

How many grams of CCL4 were formed? 116.9 g

How many grams of Cl2 reacted with the CH4? 243.8 g

Explanation:

First we need to know the molar mass for every element or compound in the reaction:

Now we proceed to calculate the amount of moles produced, per product:

To calculate the mass of chlorine we just need to make a mass balance:

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explanation:

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