An unbalanced chemical equation for the reaction of boron fluoride with lithium sulfite is shown below.
bf3 +li so3 → b2(so3)3 + lif
what is the coefficient of lithium fluoride in the balanced chemical reaction?
1

6

Explanation:

You have the unbalanced chemical reaction:

BF3 + Li2SO3 ⇒ B2(SO3)3 + LiF

Knowing that there are 2 atoms of boron in the products, we need to adjust that element putting 2 as coefficient of BF3.

2BF3 + Li2SO3 ⇒ B2(SO3)3 + LiF

Then, we need to balance fluor. There are 6 atoms of F in the reactants, for that reason, we write 6 in the lithium fluoride.

2BF3 + Li2SO3 ⇒ B2(SO3)3 + 6LiF

Finally, sulfur and oxygen have to be adjusted. 3 before lithium sulfite is enough to balance the chemical reaction.

2BF3 + 3Li2SO3 ⇒ B2(SO3)3 + 6LiF

the answer is c. nacl