In the absence of turbulent mixing, the partial pressure of eachconstituent of air would fall off height above sea level in theearth's atmosphere aspi=p0ie-mz/rt wherepi is the partial pressure at the heightz, p0i is the partial pressure of component iat sea level ,g is the acceleration of gravity, r is the gasconstant, t is the absolute temperature and mi is themolecular mass of the gas. as a result of turbulent mixing, thecomposition of the earth's atmosphere is constant below an altitudeof 100 km, but the total pressure decreases with altitude asp=p0e-mavegz/rt wheremave is the mean molecular weight of air. at sea level, xn2=0.78084 and xhe=0.524 andt=300k. )calculate the total pressure at 10 km assuming a mean molecularmass of 28.9 g mol-1 and that t=300k throughout thisaltitude )calculate the value thatxn2/xhe would have at 10 km in the absence ofturbulent mixing. compare your answer with correct value.