Determine the mass of chloride (mw = 35.45 g/mol ) in grams present in 100 ml of a 0.273 m solution of aqueous fecl₃ (iron(iii) chloride). express the mass in grams to three significant figures.

The mass chloride is 2.903 grams

Explanation:

Step1: calculate the moles of FeCl3

moles = molarity  x  volume  in liters

volume in liters = 100 ml /1000 =  0.1 L

molarity = 0.273  M  =  0.273  mol / L

moles   =   0.273  mol /L  x 0.1 L = 0.0273   moles

step 2:  find the moles of Cl

since there is  3  atoms of  cl in FeCl3

= 3 x 0.0273 =0.0819 moles

Step 3:  calculate  mass  of cl

 mass= moles  x molar mass

=0.0819 moles x 35.45 g/mol = 2.903 g

since the atomic number is the number of protons in the nucleus, as we move to the left on the periodic table, the electrostatic pull between the nucleus and the valence electron shell decreases. as we move down a group (vertical column), the valence shell energy level gets further and further from the nucleus.

the answer is c i believe