How many helium atoms are there in a helium blimp containing 532 kg of helium?

The answer to your question is: 8.01 x 10²⁵ atoms of helium

Explanation:

Data

Helium mass = 532 kg

Also from the periodic table:

He atomic mass = 4 gr

Avogrado's number: 6.023 x 10 ²³

Process (rule of three)

                1 mol of helium  4 kg

                x moles of helium  532 kg

x = 532 x 1 / 4 = 133 moles of helium

                1 mol of helium  6.023 x 10²³ atoms

              133 moles of helium            x            atoms of helium

atoms of helium = 133 x  6.023 x 10²³ / 1 = 8.01 x 10²⁵

a. the law of proportion states the combination of 2 atoms in a specific ratio to produce multiple compounds such as the given statement of question ‘1st compound contains 88.8 % cu ’ indicates 88.8 g of cu is present along with 11.2 g oxygen in 100 g of compound whereas the statement ‘2st compound contains 79.9 % cu ’ indicates 79.9 g of cu is present along with 20.1 g oxygen in 100 g of compound

1st compound contains 88.8 g cu

for cu

m = 63 g /mol

atomic % = 88.8 /63 = 1.42

for o

m = 16 g /mol

atomic % = 11.2 /16 = 0.7

b. the emperical formula of 1st compound is

cu1.4o0.7

cu2o

a). in this case, dh> 0 and sd> 0. if t becomes larger, the term "-tds" will become more negative. at some point, it is possible that -dts will be more negative than the dh is positive, and the reaction will become spontaneous. this is probably the correct answer, but you should look at all of the other possibilities and make sure of that.