How many moles are equal to 28 grams of caco3

N(CaCO3)=m÷M
m being the mass of the sample and M being the molar mass of the compound; Molar mass is to be obtained by adding the atomic masses of all the elements in the compound.

therefore,

n(CaCO3)=m÷M
=28g÷100 g.mol
=0.28 mol

therefore, there are 0.28 moles in 28g of Calcium Carbonate.

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