Calculate the molar solubility of pbbr2 (ksp = 4.67x10-6) in 0.10m nabr solution.

Explanation:

will dissociate into ions as follows.

Hence, for this reaction will be as follows.

We take x as the molar solubility of when we dissolve x moles of solution per liter.

Hence, ionic molarities in the saturated solution will be as follows.

                = + x

                = + 2x

So, equilibrium solubility expression will be as follows.

            =

Each sodium bromide molecule is giving one bromide ion to the solution. Therefore, one solution contains = 0.10 and there will be no lead ions. So, = 0

So, will approximately equals to .

Hence,

                        x = M

Thus, we can conclude that molar solubility of is M.