Heat transfer coefficient in evaporatora 10 wt% naoh solution is concentrated to 40 wt% in an evaporator operating at 40 kpa. the feed enters the evaporator at a mass flow rate of 4200 kg/hr and a temperature of 21.1°c. the evaporator area is 1.12 m2. saturated steam at 110°c is used for heating. a)calculate the boiling point rise (bpr) in the evaporator; b)calculate the steam flow rate in kg/hr; c)calculate the overall heat transfer coefficient in units of w/(m2*k).

- decrease the number of plants and animals living in the water.

the answer is b & c i believe : )

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

water and alcohols have similar properties because water molecules contain hydroxyl groups that can form hydrogen bonds with other water molecules and with alcohol molecules, and likewise alcohol molecules can form hydrogen bonds with other alcohol molecules as well as with water.