The molar concentration of a sugar solution in an open beaker has been determined to be 0.3m. calculate the solute potential at 27 degrees. round your answer to the nearest hundredth.

- 7.48

Explanation:

Given:

Concentration of the sugar solution, C = 0.3 M

Temperature, T = 27° C = 273 + 27 = 300 K

Now,

The solute potential is given as:

solute potential = - iCRT

where,

i is the number of particles the particular molecule will make in water

i = 1 for sugar

R is the universal gas constant = 0.0831 liter bar/mole-K

on substituting the respective values, we get

solute potential = - 1 × 0.3 × 0.0831 × 300

or

The solute potential = - 7.479 ≈ - 7.48

the answer is 303.15 or 303