Aflask contains 2.0 mol of he gas at 25°c and 1.00 atm. how much he gas, in grams, must be added to increase the pressure to 2.00 atm at constant temperature and volume?

Mass of He required = 8.0 g

Explanation:

Given,

Initial moles of He = 2.0 mol

Initial pressure = 1.00 atm

final pressure = 2.00 atm

Ideal gas equation,

PV = nRT

As V, R and T are constant

So,

Molar mass of He = 4.00 g/mol

No. of moles of He needs to be added = 4.0 - 2.0 = 2.0 mol

Mass = No. of mole × Molar mass

         = 2.0 × 4.0

          = 8.0 g

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