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Chemistry, 05.09.2019 04:10 mollykay2001p3qo0j

Molecular iodine, i2(g), dissociates into iodine atoms at 625 k with a first-order rate constant of 0.271 s−1.
(a) what is the half-life for this reaction?
(b) if you start with 0.052 m i2 at this temperature, how much will remain after 5.16 s assuming that the iodine atoms do not recombine to form i2?

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Molecular iodine, i2(g), dissociates into iodine atoms at 625 k with a first-order rate constant of...
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