The combustion of ethanol (c2h5oh) takes place by the following reaction equation.
c2h5oh (l) + 3 o2 (g) → 2 co2 (g) + 3 h2o (g)
what is the volume of co2 gas produced by the combustion of excess ethanol by 23.3 grams of o2 gas at 25°c and 1.25 atm?

Explanation:

We will need a balanced chemical equation with masses and molar masses, volumes, and concentrations, so, let's gather all the information in one place.

M_r:                         32.00

           C₂H₅OH(l) + 3O₂(g) → 2CO₂(g) + 3H₂O(g)

m/g:                          23.3

(a) Moles of O₂

(b) Moles of CO₂

The molar ratio is 2 mol CO₂ = 3 mol O₂

(c) Volume of CO₂

We can use the Ideal Gas Law to calculate the volume.

T = 25 °C = 298.15 K

the answer is na (sodium)

he uptake of drugs from the intestine is often strongly influenced by diffusion. for example, consider a water-insoluble steroid for treating inflammation that is solubilized in aggregates of detergent molecules, called micelles. these micelles, aggregates of 80 soap molecules, have a molecular weight of 24,000, a diameter of 2.6 nm, and a charge of -27. the positively charge ions (counterions) in this system are na".