If 14.5 kj of heat were added to 485 g of liquid water, how much would its temperature increase?

The increase in temperature is 7.14°C

Explanation:

To calculate the change in temperature, we use the equation:

where,

q = heat absorbed = 14.5 kJ = 14500 J    (Conversion factor: 1 kJ = 1000 J)

m = mass of water = 485 g g

c = specific heat capacity of water = 4.184 J/g.°C

= change in temperature = ?

Putting values in above equation, we get:

Hence, the increase in temperature is 7.14°C

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explanation:

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