Calculate the heat capacity, in joules and in calories per degree, of the following:
(a)28.4 g of wate
(b)1.00 oz of lead

Explanation:

Heat capacity is defined as the amount of heat required to raise the temperature of a substance by 1 degree celsius.

(a)   It is known that specific heat of water is 4.184 .

Hence, heat capacity in joules and in calories per degree for 28.4 g of water will be as follows.

              =

In calories,

                   = 28.4

(b)   In 1 oz there are 28.3 grams. And, heat capacity of lead is 0.129 .

Hence, heat capacity in joules and in calories per degree for 1 oz or 28.3 g of lead will be as follows.

                     =

In calories,

                   = 0.882

sure what is it? ^w^

the answer is b & c i believe : )