What mass of ca(oh)2 will react with 25.0 g of phosphoric acid to form the preservative calcium propionate according to the equation?

The mass of calcium hydroxide reacted is 28.305 g

Explanation:

To calculate the number of moles, we use the equation:

    .....(1)

Given mass of phosphoric acid = 25 g

Molar mass of phosphoric acid = 98 g/mol

Putting values in equation 1, we get:

The chemical equation for the reaction of phosphoric acid and calcium hydroxide follows:

By Stoichiometry of the reaction:

2 moles of phosphoric acid reacts with 3 moles of calcium hydroxide.

So, 0.255 moles of phosphoric acid will react with = of calcium hydroxide.

Now, calculating the mass of calcium hydroxide from equation 1, we get:

Molar mass of calcium hydroxide = 74 g/mol

Moles of calcium hydroxide = 0.3825 moles

Putting values in equation 1, we get:

Hence, the mass of calcium hydroxide reacted is 28.305 g