Copper(i) iodine (cul) is often added to the table salt as a dietary source of iodine. how many moles of cul are contained in 1.00 lb (454 g) of table salt containing 0.0100% by mass?

0.238 millimoles

Explanation:

Given:

Mass of the table salt = 1.00 lb = 454 g

Copper(I) Iodine (cul) present in the table = 0.0100% by mass

or

Copper(I) Iodine (cul) present in the 1 pound of salt = 0.01% of 454 g

= 0.0454 grams

Molar mass of the CuI = 63.54 grams + 126.90 grams = 190.44 grams

Thus,

the number of moles of CuI present in 1 pound of salt = Mass / Molar mass

= 0.0454 / 190.44

= 2.38 × 10⁻⁴ moles

= 0.238 millimoles

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :