Calculate the molarity of each of the following solutions:
(a) 0.195 g of cholestrol, c27h46o, in 0.100 l of serum, the average concentration of cholestrol in human serum
(b) 4.25 gram of nh3 in 0.500 l solution, the concentration of nh3 in household ammonia
(c) 1.49 kg of isopropyl alcohol c3h7oh in 2.50 l of solution the concentration of isopropyl alcohol in rubbing alcohol
(d)0.029 gram of i2 in 0.100 l of solution the solubility of i2 in water at 20 c

For a: The molarity of solution is 0.005 M.

For b: The molarity of solution is 0.5 M.

For c: The molarity of solution is 9.92 M.

For d: The molarity of solution is 0.0011 M.

Explanation:

To calculate the molarity of solution, we use the equation:

 .....(1)

Mass of cholestrol = 0.195 g

Molar mass of cholestrol = 386.65 g/mol

Volume of solution = 0.100 L

Putting values in equation 1, we get:

Hence, the molarity of solution is 0.005 M.

Mass of ammonia = 4.25 g

Molar mass of ammonia = 17 g/mol

Volume of solution = 0.500 L

Putting values in equation 1, we get:

Hence, the molarity of solution is 0.5 M.

Mass of isopropyl alcohol = 1.49 kg = 1490 g  (Conversion factor: 1 kg = 1000 g)  

Molar mass of isopropyl alcohol = 60.1 g/mol

Volume of solution = 2.5 L    

Putting values in equation 1, we get:

Hence, the molarity of solution is 9.92 M.

Mass of iodine = 0.029 g

Molar mass of iodine = 253.8 g/mol

Volume of solution = 0.100 L

Putting values in equation 1, we get:

Hence, the molarity of solution is 0.0011 M.

dynamic equilibrium is the answer.

for step 7 table c on the lab "newtons law of action"   the average time it took the car to travel .25 meters   was 1.92 seconds.

the average time it took the car to travel 0.50 meters was 2.61 seconds

hope this : )