The accepted length of a steel pipe is 6.7 m. calculate the percent error of each of these measurements.
a. 6.8 m
b. 6.1 m
c. 6.7 m
d. 6.6 m

a. 1.49%

b. -8.95%

c. 0%

d. -1.49%

Explanation:

a. Actual length = 6.7 m

Measured length = 6.8 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.8-6.7)/6.7 * 100 = 0.1/6.7 * 100 = 1.49%

b. Actual length = 6.7 m

Measured length = 6.1 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.1-6.7)/6.7 * 100 = -0.6/6.7 * 100 = -8.95%

c. Actual length = 6.7 m

Measured length = 6.7 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.7-6.7)/6.7 * 100 = 0.1/6.7 * 100 = 0%

a. Actual length = 6.7 m

Measured length = 6.6 m

% error = (Measured length - Actual Length)/Actual Length * 100

= (6.6-6.7)/6.7 * 100 = -0.1/6.7 * 100 = -1.49%

- lead + phosphoric acid = hydrogen + lead(ii) phosphate

a electronegativity decreases beacuse the size of nucleus is bigger.