3. calculate the potentiai of the cell indicated using the line notation below. pt(s) 12(s)|1 (aq, 1.0 m) || cr2o,2-(aq, 2.0 m), cr (aq, 1.0x10 m), h'(aq, 1.0 m)| pt(s) cr2o72 (aq)+14h*(aq) + 6e + 2cr (aq)+7h20() e+1.33 v eo +0.54 v 2(s)2e 21(aq) +

Variables,control,conclusion and finally scientific theory

Ineed with this also i hope you understand it

Answerthis solution will not form a precipitateexplanationsolubility equilbrium:         pbf₂(s)  ⇄ pb²⁺(aq) + 2 f⁻(aq)the solubility product expression is    (we exclude solids from the equilibrium expression).now suppose we have the trial ion product q, which we can define as    then, we can interpret  q as the product of the concentration of the ions that we have and ksp as the product of the ion concentrations that are needed to form a saturated solution.if q > ksp, then that implies that there will be a surplus of ions that exceed the amount that is required to form a saturated solution. a precipitate will then form (the precipitate continually  forms until the surplus ions are removed and q is decreased to ksp's value).if q = ksp, the saturated solution that forms is barely saturated and the precipitate will be minimal.if q < ksp, then the ion concentration will not be enough to form a saturated solution (so no precipitate).using our information, we calculate the trial ion product:     since q = 2.7  × 10⁻⁸ < ksp =  4  ×  10⁻⁸, a precipitate will not form.