What mass of oxygen will react with 25.0 g of ch3oh? 0/1 point boo o 2ch3oh + 302 - 2002 + 4h20 16.65 18.75 37.55 8.325 o in o n ! incorrect

37.44 g

Explanation:

According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP, contains avogadro's number of particles and weighs equal to the molecular mass.

To calculate the moles, we use the equation:

According to stoichiometry:

2 moles of methanol react with 3 moles of oxygen

Thus 0.78 moles of methanol will react with=  moles of oxygen

Mass of oxygen =

Thus 37.44 g of oxygen will react with 25.0 g of