Consider the following redox reaction: (38) cus + no3 → cuso4 + no2 which of the following statement is false? [1] [2] [3] cu has an oxidation state of +2 in cus. cu has an oxidation state of +2 in cuso4. s is oxidized in the above reaction. electrons are donated from s in cus to n in no3". none of the above.

Answer : The answer is none of the above.

Explanation :

Redox reaction or Oxidation-reduction reaction : It is defined as the reaction in which the oxidation and reduction reaction takes place simultaneously.

Oxidation reaction : It is defined as the reaction in which a substance looses its electrons. In this, oxidation state of an element increases. Or we can say that in oxidation, the loss of electrons takes place.

Reduction reaction : It is defined as the reaction in which a substance gains electrons. In this, oxidation state of an element decreases. Or we can say that in reduction, the gain of electrons takes place.

The given balanced chemical reaction is :

The oxidation state of 'Cu' in and is, (+2).

In this reaction, the oxidation state of 'S' changes from (-2) to (+6) that means 'S' lost 4 electrons and it shows oxidation and the oxidation state of 'N' changes from (+5) to (+4) that means 'N' gains 1 electron and it shows reduction.  That means electrons are donated from 'S' in CuS to 'N' in .

The oxidation-reduction half reaction will be :

Oxidation :

Reduction :

All the given statements are correct.

Hence, the answer is none of the above.