Chemistry, 30.08.2019 03:20 sharri44

Calculate the mass of vanadium(v) oxide (v2o5) that contains a million (1.0 *10^6) vanadium atoms. be sure your answer has a unit symbol if necessary, and round it to 3 significant digits.

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Answer from: helpmeplzz27

Answer : The mass of vanadium(V) oxide will be $1.51\times 10^{-16}g$

Explanation : Given,

Number of atoms of V_2O_5 = $1.0\times 10^{6}$

Molar mass of V_2O_5 = 181.88 g/mole

In V_2O_5 , there are 2 atoms of vanadium and 5 atoms of oxygen.

First we have to determine the moles of V_2O_5 .

As, $2\times 6.022\times 10^{23}$ number of vanadium atom present in 1 moles of V_2O_5

So, $1.0\times 10^{6}$ number of vanadium atom present in $\frac{1.0\times 10^{6}}{2\times 6.022\times 10^{23}}=8.3\times 10^{-19}$ moles of V_2O_5

Now we have to determine the mass of V_2O_5 .

$\text{Mass of }V_2O_5=\text{Moles of }V_2O_5\times \text{Molar mass of }V_2O_5$

$\text{Mass of }V_2O_5=(8.3\times 10^{-19}mole)\times (181.88g/mole)=1.51\times 10^{-16}g$

Therefore, the mass of vanadium(V) oxide will be $1.51\times 10^{-16}g$

Answer from: pesinaic

Explanation:

It is known that molar mass of $V_{2}O_{5}$ is 181.88 g/mol.

We will calculate the number of vanadium atoms present in 1 mole of $V_{2}O_{5}$ as follows.

$2 \times 6.022 \times 10^{23}$ atoms

= $12.044 \times 10^{23}$ atoms

Therefore, mass of $V_{2}O_{5}$ which contains $12.044 \times 10^{23}$ atoms of vanadium = Molar mass of $V_{2}O_{5}$ = 181.88 g/mol.

Hence, we will calculate the mass of $V_{2}O_{5}$ that contains $1.0 \times 10^{6}$ vanadium atoms as follows.

$\frac{181.88 g/mol \times 1.0 \times 10^{6} atoms}{12.044 \times 10^{23}atoms}$

= $15.1 \times 10^{-17}$

Thus, we can conclude that mass of $V_{2}O_{5}$ in given situation is $15.1 \times 10^{-17}$ g/mol.

Answer from: Quest

water molecules stay close to each other through cohesion, the collective action of hydrogen bonds between water molecules. cohesion plants draw water upwards from the root through the stem's transport tubes (xylem) to the leaf. this transport occurs even in large trees and against gravity. transpiration, evaporation of water from plant leaves, creates a tension on water molecules being pulled up from the stem and roots.

water also has high (the attraction of one substance to another) properties because of its polar nature. adhesion of water molecules to plant cell walls counteract gravity while water is transported from roots to leaves.

water exhibits a very high surface tension when compared to other liquids. surface tension is a property of a liquid that holds the surface together and allows it to resist an external force. by capillary action, the water forms concave menisci inside the pores. the high surface tension of water pulls the concavity outwards, generating enough force to lift water from the roots to the leaves of plants.

thus, cohesion, along with adhesion and surface tension creates a capillary action that keeps water molecules interacting and moving through the plants out to the leaf cells.

therefore, option d) is the correct answer.

explanation:

Answer from: Quest

A, it is falling action my have a good day

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Calculate the mass of vanadium(v) oxide (v2o5) that contains a million (1.0 *10^6) vanadium atoms. b...

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