For a reaction in a voltaic cell, both δh° and δs° are positive. given the following equations for standard free energy, δg° =δh° -tδs° ; δg° = -nfe° . how does the standard cell potential change with increasing temperature? derive the equation that shows how the standard cell potential change with temperature

The standard cell potential increases with increasing temperature.

Explanation:

Equatio 1: ΔG° =ΔH° -TΔS°

Equation 2:  ΔG° = -nFE°

Isolating E° in equation 2:

E° = - ΔG° / nF (Equation 3)

Substituting equation 1 in equation 3:

E° = (- ΔH° +TΔS°)/ nf

We can rearrange the equation:

E° = (ΔS°/nF) T + (ΔH°/nF)

Now it is clear that the higher the temperature, the higher the standard cell potential.

answer

i think the answer is a) as air pressure in an area increases, the density of the gas particles in that area decreases.

hope it

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