What is the molar mass of a gas which occupies 48.7 l at 111oc under 698 torr of pressure and has a mass of 21.5 grams?

Molar mass of the gas = 15.15 g/mol

Explanation:

PV = nRT

Where,

P = pressure

n = No. of moles

R = Gas constant

T = Temperature

P = 698 torr, 1 torr = 0.00131579 atm

Temperature = 111 °C = 100 + 273.15 = 384.15 K

V = 48.7 L

R = 0.082057 L atm/mol K

Now, PV = nRT

          =1.4189 mol

Molar mass = Mass/ No. of  moles

                    = 21.5/1.4189

                    =15.15 g/mol

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