break down the following question in a step by step easy to comprehend process.
when one atom of iodine-131 decays by beta particle emission, 1.5541 x 10^ -33 j are released. the atomic mass of the product nuclide is 130.9051 atomic mass units. write a nuclear reaction for the decay of iodine-131 and determine its atomic mass in amu. 1 amu = 1.66053886 x 10^ -27kg; mass of a b particle = 9.10938291 x 10^ -31kg

The atomic mass of  iodine-131 is 130.9056485 amu.

Explanation:

Beta-decay is the process in which a neutron gets converted into a proton and an electron releasing a beta-particle. The beta particle released carries a charge of -1 units.

Energy released during beta particle emission = E

Mass of reactant = Mass of product + Δm

=  Mass of beta particle + nuclide + Δm

Mass Beta-particle =

Mass of reactant =

=130.9051+0.000548579 amu + amu

= 130.9056485 amu

The atomic mass of  iodine-131 is 130.9056485 amu.

specific gravity is the density of a substance divided by the density of water. since (at standard temperature and pressure) water has a density of 1 gram/cm3, and since all of the units cancel, specific gravity is usually very close to the same value as density

so "c" is the answer

plz give brainliest