Aqueous solutions of sodium hypoch lorite (naoci), best known as bleach, are prepared by the reaction of sodium hydroxide with chlorine: 2 naoh (aq)cl2(g)-> naoci (aq)+ h20 (i)+ nacl (aq) how many grams of naoh are needed to react with 25.0 g of chlorine?

28.2 g of NaOH

Explanation:

We need to calculate the grams of NaOH needed to react with 25.0 g of Cl₂ in the following reaction:

2 NaOH(aq) + Cl₂(g) → NaOCI(aq + H₂0(I) + NaCl(aq)

We are going to solve this by making use of the molar ratio between Cl₂ and NaOH given by the reaction equation where we see that every mol of Cl₂ will react with 2 moles of NaOH.

So first we need to convert the 25.0 g of Cl₂ to moles:

Then we need to calculate the moles of NaOH needed to react with these moles of Cl₂ knowing that every mol of Cl₂ will react with 2 moles of NaOH:

Next we must convert these moles to grams:

28.2 g are needed to react with 25.0 g of Cl₂ in the production of NaOCl

that's just how they are

explanation:

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