the given graduated cylinder is calibrated in
milliliters (ml).
determine the volume of liquid in the graduated cylinder
and report it to the correct number of significant figures.

Explanation:

To measure correctly the volume of a liquid in a graduated cylinder, you must follow these recomendations:

The first and second recomendations are supposed to be correctly handled to take the picture. So, you must now follow the recomendations about reading around the bottom of the meniscus.

In the figure the bottom of the meniscus is between the marks 24 ml and 25 ml, so the correct measurement is (24ml + 25ml)/2 = 24.5 ml.

As you see, although the cylinder is calibrated to read 1 ml, you can appreciate up to half one miliiter, 0.5 ml.

The correct number of significant figures includes the certain digits (24) and one uncertain figure: the decimal 5.

Conclusion: Hence, the volume reported with the correct number of significant figures is 24.5 ml

The volume of the liquid in the cylinder is 24 mL.

The measuring cylinder is a standard apparatus used to measure the volume of a liquid. The measuring cylinder is transparent thereby making it easy to read off the volume of a liquid.

Looking at the measuring cylinder as shown, the volume of the liquid in the cylinder is 24mL. We read this off by looking at the position of the lower meniscus of the fluid.

Learn more: link

first let us lay out the formula for potential

and kinetic energy:

pe = mgh

ke = (mv^2)/2

where: m=mass, v=velocity, g=gravitational

acceleration, h=height

calculating for mass using the known values of

pe:

340j = m (9.81 m/s^2) (50ft) (1m/3.28ft)

m = 2.27 kg

the law of conservation of energy states that

energy is neither created nor destroyed. therefore, the change in kinetic

energy from 50 ft to 35 ft would be equal to the change in potential energy

from 50 ft to 35 ft. however it would be opposite in signs since one is losing

while other is gaining.

ke(35ft) – ke(50ft) = - [ pe(35ft) – pe(50ft]

ke(50ft) = 0 since the brick is initially at rest

ke(35ft) = 340j - 2.27kg (9.81 m/s^2) (35ft)

(1m/3.28 ft)

ke(35ft)

= 102.38 j

10 years is the answer