Five moles of monatomic ideal gas have initial pressure 2.50 * 103 pa and initial volume 2.10 m3. while undergoing an adiabatic expansion, the gas does 1480 j of work. what is the final pressure of the gas after the expansion?

pressure of the gas after the expansion is 1795.238 Pa

Explanation:

adiabatic expansion W(+) -  ideal gas:

deriving (1):

⇒ PdV + VdP = RndT

⇒ PdV = RndT - VdP

being the T constant ⇒ dT = 0

⇒ PdV = - VdP(3)

(3) in (1):

⇒ W = ∫ (- VdP )

⇒ W = - V ∫dP

⇒ W = - V * ( P2 - P1 )

⇒ P2 = - ( W / V ) + P1

⇒ P2 = - ( 1480 J / 2,1 m³ ) + 2.5 E3 J /m³

⇒ P2 =  - 704.762 J/m³ + 2.5 E3 J/m³

⇒ P2 = 1795.238 Pa

the electrical  conductivity  of asolution  of an electrolyte is measured by determining the resistance of thesolution  between two flat or cylindrical electrodes separated by a fixed distance.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2