Calculate the mass defect for the formation of phosphorus-31. the mass of a phosphorus-31 nucleus is 30.973765 amu. the masses of a proton and a neutron are 1.00728 and 1.00866 amu, respectively. enter your answer in amu's with five decimal places and no units.

The mass defect for the formation of phosphorus-31 is 0.27399

Explanation:

Mass defect is defined as the difference in the mass of an isotope and its mass number.

The equation used to calculate mass defect follows:

where,

= number of protons

= mass of one proton

= number of neutrons

= mass of one neutron

M = mass number of element

We are given:

An isotope of phosphorus which is

Number of protons = atomic number = 15

Number of neutrons = Mass number - atomic number = 31 - 15 = 16

Mass of proton = 1.00728 amu

Mass of neutron = 1.00866 amu

Mass number of phosphorus = 30.973765 amu

Putting values in above equation, we get:

Hence, the mass defect for the formation of phosphorus-31 is 0.27399