Chemistry, 19.08.2019 22:20 RegencySlayer5304
Acertain reaction has an activation energy of 66.41 kj/mol. at what kelvin temperature will the reaction proceed 3.00 times faster than it did at 293 k?
Answers: 1
![\log (\frac{K_2}{K_1})=\frac{Ea}{2.303\times R}[\frac{1}{T_1}-\frac{1}{T_2}]](/tpl/images/0179/9186/6d953.png)
= rate constant at 
Ā = 
= rate constant at 
= 
= activation energy for the reaction = 66.41 kJ/mole = 66410 J/mole![\log (\frac{3K_1}{K_1})=\frac{66410J/mole}{2.303\times 8.314J/mole.K}[\frac{1}{293K}-\frac{1}{T_2}]](/tpl/images/0179/9186/a03fc.png)
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Acertain reaction has an activation energy of 66.41 kj/mol. at what kelvin temperature will the reac...
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