Below is a proposed mechanism for the decomposition of h2o2. h2o2 + i– → h2o + io– slow h2o2 + io– → h2o + o2 + i– fast which of the following statements is incorrect? a. io– is a catalyst. b. the reaction is first-order with respect to [i–]. c. the reaction is first-order with respect to [h2o2]. d. the net reaction is 2h2o2 → 2h2o + o2. e. i– is a catalyst.

Option (d) is the correct answer.

Explanation:

The given equations as as follows.

                  (slow)

Therefore, overall reaction equation will be as follows.

So, cancelling the spectator ions then the equation will be as follows.

As, it is known that slow step of a reaction is the rate determining step. Therefore, rate law for the slow step will be as follows.

                 Rate law =

Hence, the reaction is first order with respect to and it is also first order reaction with respect to .

Also, acts as a catalyst in the reaction.

Thus, we can conclude that the incorrect statement is is a catalyst.

as given the equation is

2al + 6 hcl > 2 alcl3 + 3 h2(g)

as per equation two moles of aluminum reacts with six moles of hcl to give two moles of alcl3 and three moles of hydrogen gas

given: three moles of al are present and 7 moles of hcl

for three moles of aluminum nine moles of hcl will be required

however as 7 moles of hcl are present so the limiting reagent is hcl

hcl is going to decide the number of moles of product formed

when six moles of hcl are present = 3 moles of h2 are formed

when one mole of hcl is present == 3/6 mole sof h2 will be formed

when 7 moles of hcl are present = 3 x 7/ 6 moles of h2 will be formed = 3.5 moles of h2