The acid dissociation ka of propionic acid c2h5co2h is 1.310x10−5. calculate the ph of a 3.010x10−4m aqueous solution of propionic acid. round your answer to 2 decimal places.

Answer : The pH of the solution is, 4.25

Solution :  Given,

Concentration (C) =

Acid dissociation constant =

The equilibrium reaction for dissociation of (weak acid) is,

initially conc.        c                       0                0

At eqm.                                             

where, is degree of dissociation

First we have to calculate the value of

Now put all the given values in this formula, we get:

Now we have to calculate the hydrogen ion concentration.

Now we have to calculate the pH.

Therefore, the pH of the solution is, 4.25

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explanation:

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the answer is either b or c