Consider the following redox equation mn(oh)2(s) + mno4 –(aq)  mno42 –(aq) (basic solution) when the equation is balanced with smallest whole number coefficients, what is the coefficient for oh –(aq) and on which side of the equation is oh –(aq) present?

Answer : The balanced chemical equation is,

The coefficient for is, 4 and on reactant side of the equation is present.

Explanation :

Rules for the balanced chemical equation in basic solution are :

The half reactions in the basic solution are :

Reduction : ......(1)

Oxidation : .....(2)

Now multiply the equation (1) by 2 and then added both equation, we get the balanced redox reaction.

The balanced chemical equation in a basic solution will be,

Thus, the coefficient for is, 4 and on reactant side of the equation is present.

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