The mercury content of a stream was belived to be above the minimum considered safe part per billion (ppb) by weight. an analysis indicated that the concentration was 0.68 parts per billion. what quantity of mercury in grams was persent in 15.0 l of the water, the density of which is 0.998 g/ml? (1 ppb hg = 1nghg/1g water)

Quantity of Hg in 15.00 L water = 1.0*10^-5 g

Explanation:

Given:

Concentration of Hg = 0.68 parts per billion (ppb)

Volume of water = 15.0 L

Density of water = 0.998 g/ml

To determine:

The amount of Hg in 15.0 L of water

Calculation:

1 ppb = 1 nanogram (ng) solute/1 g water

1 ng = 10⁻⁹ g

0.68 ppb = 0.68 ngHg/1 g water = 0.68*10⁻⁹g Hg/ 1g water

The amount of Hg in the above mass of water would be:

=

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.

10 years is the answer