Explain why unbranched alkenes can form geometric isomers while unbranched alkanes cannot. does this explanation involve the macroscopic domain or the microscopic domain?

answer: the value of enthalpy change will be -152.80 kj.

solution:

pressure = 1atm , temperature = = 298 k

given that pressure and temperature are same in both gases , the number of moles of both gases can be determined by the ideal gas equation.

according to reaction 3 moles no are reacting with 1 mol of ,then 0.49 mol of no will react with moles of ozone that is 0.16 moles of ozone. since, no is limiting reagent and is an excessive reagent.

enthalpy change for the reaction between the given volumes of the gases is :

it should have an internal chamber and two thermometers sticking out of the top. the internal chamber will also be closed off from the outside.