The henry's law constant (kh) for o2 in water at 20°c is 1.28e-3 mol/l atm. how many grams of o2 will dissolve in 3.5 l of h2o that is in contact with pure o2 at 1.65 atm?

Answer : The mass of dissolved will be, 0.2365 grams

Explanation :

First we have to calculate the concentration of .

As we know that,

where,

= concentration of = ?

= partial pressure of = 1.65 atm

= Henry's law constant =

Now put all the given values in the above formula, we get:

The concentration of =

Now we have to calculate the moles of

Now we have to calculate the mass of

Therefore, the mass of dissolved will be, 0.2365 grams

the ideal gas law equation is as follows

pv = nrt

where p - pressure

v - volume

n - number of moles

r - universal gas constant

t - temperature

so if the pressure, volume and temperature are already known

we are left with n and r

since r is the universal gas constant that has a known fixed value then r too is known

so we are left with 'n'

once we know temperature volume and pressure

we can find the number of moles of gas present using the ideal gas law equation

this is not my own answer, this is an answer for the same question by the user blahblahmali. i do not claim ownership of this account.