Use tabulated electrode potentials to calculate δg∘ for the following reaction: 2na(s)+2h2o(l)→h2(g)+2oh−(aq)+2na+( aq) express the free energy in joules to three significant figures.

The for the given reaction is

Explanation:

For the given chemical reaction:

Half reactions for the given cell follows:

Oxidation half reaction:    (  × 2)

Reduction half reaction:

Oxidation reaction occurs at anode and reduction reaction occurs at cathode.

To calculate the of the reaction, we use the equation:

Putting values in above equation, we get:

Where,

n = number of electrons transferred = 2

F = Faradays constant = 96500 C

= standard cell potential = 2.71 V

Putting values in above equation, we get:

Hence, the for the given reaction is

nuclear fission produces elements that are heavier than helium.

the elements that are used in nuclear fission and their products are much heavier than helium.