Calculate the solubility (in g/l) of silver carbonate in water at 25°c if the ksp for ag2co3 is 8.4 x 10-12, a) 8.0 x 10-4 g/l b) 3.5 x 10-2 g/l c)4.4 × 10-2g/l d) 5.6 x 10-2 g/l

S = 5.6 E-2 g / L

Explanation:

⇒         S                 2S       S

⇒ Kps = 2S*S = 2S² = 8.4 E-12

⇒ S² = 8.4 E-12 / 2

⇒ S² = 4.2 E-12

⇒ S = √4.2 E-12

⇒ S = 2.05 E-6 mmol / mL

⇒ S = 2.05 E-6 mmol / mL * 0.001 mol / mmol * 275.7453 g Ag2CO3 / mol * 1000mL / L

⇒S = 5.651E-2 g / L

not clear