The solubility of pb(no 3) 2 is 55 grams per 100 g h 2o at 20°c. which term would properly describe a solution where 44 grams of pb(no 3) 2 is added to 100 grams of water at this temperature?

The solution is unsaturated.

Explanation:

Amount dissolved > Maximum solubility limit, the solution is saturated.

Amount dissolved < Maximum solubility limit, the solution is unsaturated.

44 g of Pb(NO₃)₂ is added to 100 g of water, the solution is:

Solubility of the Pb(NO₃)₂ given at 20 °C = 55 g/100 g water.

It means:

100 g of water can dissolve maximum of 55 g of  Pb(NO₃)₂

It means,

Maximum amount of Pb(NO₃)₂ that can be dissolved = 55 g

Actual amount dissolved = 44 g

Since,  

Amount dissolved < Maximum solubility limit

44 g > 55 g

According to definition, the solution is unsaturated.

when the volume of gas is   changed from   717.73 ml   to 852 ml   the temperature will   change   from 315   c to 452   c

    calculation

this is calculated using the charles law formula

that is,   v1/t1 = v2/t2

          v1=?

        t1 = 315 c   into   kelvin = 315 +273 = 588 k

        v2 = 852   ml

        t2 = 425c + 273 =698 k

make v1   the subject of the formula ( by   multiplying both side by t1)

  v1=( v2 xt1) / t2

v1= (852 ml   x 588 k)/ 698 k= 717.73 ml

i don,t know so just answer mine