11.6 moles of an ideal gas are at a temperature of 298 k and a pressure of 0.91 atm, what volume would
the gas occupy, in liters? (2 points)
0 0.282
0 301
0 31
0 31

311.87 L  

Explanation:

When the gas is ideal, we applied general gas equation

PV=nRT

P= pressure

V= volume

n= number of moles of ideal gas

R=  ideal gas constant

T= temperature

Given data:

n= 11.6 mole

P= 0.91 atm

T= 298 K

R= 0.0821 dm3 atm K-1 mol-1

V= ?

By putting the values, we will get required volume

V= nRT / P

V= 11.6 mol×0.0821 dm3 atm k-1 mol-1×298 K/ 0.91 atm

V= 283.80 dm3/ 0.91

V= 311.87 L

dm3= L

the answer is the first option

explanation:

just googled it m8. not that hard

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