Two samples of potassium iodide are decomposed into their constituent elements. the first sample produced 13.0 g of potassium and 42.3 g of iodine. if the second sample produced 24.4 kg of potassium, how many kg of iodine were produced?

79.46kg of Iodine will be produced in the reaction.

These are substances which can't be broken down into smaller matter and is usually very pure.

Atomic mass of potassium =39 g/mol

Atomic mass of iodine = 127 g/mol

Moles of K produced = ?

Moles of I produced =  ?

The moles of K produced = mass/molar mass

= 13/39

= 0.33

Moles of I produced=  mass/molar mass

=42.3/127

= 0.33

Mole ratio of K:I = 1:1

The moles of K produced by second sample = mass/molar mass =

= 24.4 × 10³ / 39 = 0.626mol

The mass of Iodine produced = moles X atomic mass

= 0.626  X 127= 79.46 kg

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