Hydrogen peroxide decomposes into water and oxygen in a first-order process. h2o2(aq) --> h2o(l) + 1/2 o2(g)at 20.0 °c, the half-life for the reaction is 3.92 x 104 seconds. if the initial concentration of hydrogen peroxide is 0.52 m, what is the concentration after 7.00 days? 1.2 x 10-5 m0.034 m0.074 m0.22 m0.52 m

Concentration of after 7.00 days is M

Explanation:

Integrated rate equation for decomposition of is-

where [] is concentration of after "t" time, is initial concentration of and is half-life

Here is 0.52 M, t is 604800 second (7 days) and is 39200 seconds

Plug in all the values in the above equation-

or, =

So concentration of after 7.00 days is M

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