Calculate the entropy change for the surroundings of the reaction below at 350k: n2(g) + 3h2(g) -> 2nh3(g) entropy data: nh3 = 192.5 j/mol k h2 = 130.6 j/mol k n2 = 191.5 j/mol k

Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K

Explanation :

We have to calculate the entropy change of reaction .

where,

= entropy of reaction = ?

n = number of moles

= standard entropy of

= standard entropy of

= standard entropy of

Now put all the given values in this expression, we get:

Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K

answer; protein;

answer: enthalpy

explanation:

for a exothermic reaction, the energy is released i.e. the energy of the products is lower than the energy of the reactants.

= enthaply

= energy of products

= energy of reactants

as , thus comes out to be negative. negative value of enthalpy shows that the reaction is exothermic.