How many grams of barium sulfate can be produced from the reaction of 2.54 grams sodium sulfate and 2.54 g barium chloride? na2so4(aq) + bacl2(aq) --> baso4(s) + 2nacl(aq) report your answer to 3 decimal places.

2.796 grams

Explanation:

According to stoichiometry:

1 mole of reacts with 1 mole of

0.012 moles of will react with= of

Thus is the limiting reagent as it limits the formation of product.  is the excess reagent as (0.018-0.012)=0.006 moles are left unused.

1 mole of produces 1 mole of

0.012 moles of will produce= of

Mass of

Thus 2.796 grams of  are produced.

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