The enthalpy change for converting 10.0 g of ice at -25.0°c to water at 80.0°c is kj. the specific heats of ice, water, and steam are 2.09 j/gk, 4.18 j/gk, and 1.84 j/gk, respectively. for h2o, δhfus = 6.01 kj/mol, and δhvap = 40.67 kj/mol.

Answer : The enthalpy change is, 7.205 KJ

Solution :

The conversions involved in this process are :

Now we have to calculate the enthalpy change.

where,

= enthalpy change = ?

m = mass of water = 10 g

= specific heat of solid water = 2.09 J/gk

= specific heat of liquid water = 4.18 J/gk

n = number of moles of water =

= enthalpy change for fusion = 6.01 KJ/mole = 6010 J/mole

Now put all the given values in the above expression, we get

    (1 KJ = 1000 J)

Therefore, the enthalpy change is, 7.205 KJ

the mantle

explanation:

earth is divided into three layers: the crust or the outermost layer on which we live; the underlying, middle layer - the mantle - and the core (the innermost layer of earth).

b. accuracy of the data matters alot more than its number of digits, organization or amount of detail. quantitative observation is more accepted than the qualitative observation.